Webb29 juli 2024 · Therefore, if only one man hits the target, then the probability that it was the first man is 944944. Note: We used the complement of an event to easily calculate the … Webb21 maj 2002 · The probabilities that three men hit a target are 1/6, 1/4, and 1/3, respectively. Each shoots once at the traget. If only one of them hits the traget, find the …
Solved The probability of a man hitting a target is 1/3 ... - Chegg
WebbIf the tests are statistically independent from each other, the probability of at least one incorrect rejection is approximately 99.4%. The multiple comparisons problem also applies to confidence intervals. A single confidence interval with a 95% coverage probabilitylevel will contain the true value of the parameter in 95% of samples. WebbAnswer: Probability that A hits the target = P(H / A) = 0.9 = (9 / 10) Probability that B hits the target = P(H / B) = 0.8 = (8 / 10) Probability that C hits the ... binder cover page free printable
Three persons A, B and C aim a target. The probabilities of their ...
WebbTarget will be hit (destroyed) if at least one of the two A or B hit the target. Now, both are not able to hit the target, probability = (1 - 0.6) (1 - 0.7) = (0.4) (0.3) = 0.12 . Therefore, at least one of them hits the target, probability = 1- 0.12 = 0. 88 . … WebbRight Answer is: A SOLUTION Concept: P (A̅) = 1- P (A) Calculation: Here, let probability of a man hitting target P (A) = 1/2 and Probability of another man hitting target P (B) = 1/3 So, probability of a man not hitting target = P (A̅) = 1 - 1/2 = 1/2 and Probability of another man not hitting target = P (B̅) = 1 - 1/3 = 2/3 WebbThe probability that a bomb will hit a target is 0.8. Find the probability that out of 10 bombs dropped, exactly 2 will miss the target. Advertisement Remove all ads Solution Let X = number of bombs hitting the target. p = probability that bomb will hit the target ∴ p = 0.8 = 8 10 = 4 5 ∴ q = 1 - p = 1 - 4 5 = 1 5 Given: n = 10 ∴ X ~ B ( 10, 4 5) cystic acne hard lump