WebUnder the action of a force a 2kg body moves such that its position x in meters as a function of time t is given by x = 4t4 + 3 . Then work done by the force in first two seconds is 1691 33 NTA Abhyas NTA Abhyas 2024 Work, Energy and Power Report Error A 6J B 10J C 7J D 64J Solution: x = 4t4 +3 dtdx = 44t3 + 0 v = t3 Using work energy theorem WebAnswer (1 of 3): x = t^3/3 v = dx/dt = t^2 a = dv/dt = 2t F = ma = 4t dx = t^2 dt Work done by the force = INTEG [t = 0 to 2] {F dx } = INTEG [t = 0 to 2] {4t^3} = 16 J x = t^3/3 v = dx/dt = …
A body of mass 2 kg initially at rest moves under the action
Web24 Dec 2024 · A body of mass 1 kg begins to move under the action of a time dependent force vector F = (2t i + 3t 2 j)N,where vector i and j are unit vectors along x and y axis. … WebUnder the action of force, a 2 kg body moves such that x is a function of time given by x =t3/3, x in metre, t in seconds, find the work done in first two seconds. Solution Given, x = t … entertainment weekly princess bride reunion
A body of mass 1 kg begins to move under the action of a
WebA heavy suitcase S of mass 50 kg is moving along a horizontal floor under the action of a force of magnitude P newtons. The force acts at 30° to the floor, as shown in the diagram above, and S moves in a straight line at constant speed. The suitcase is modelled as a particle and the floor as a rough horizontal plane. WebQ: Under the action of force 2 kg body moves such that its position ‘x’ varies as a function of time t given by x= t 3 /3, x is the meter and t in second. Calculate the workdone by the … WebUnder the action of a force, a 2 kg body moves such that its position x in meters as a function of time t in seconds given by: x=t 2/2. The work done by the force in the first 5 … dr hammer chiropractor